11130402000131 has 4 divisors (see below), whose sum is σ = 11130435064512. Its totient is φ = 11130368935752.

The previous prime is 11130402000121. The next prime is 11130402000199. The reversal of 11130402000131 is 13100020403111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11130402000131 - 2³⁸ = 10855524093187 is a prime.

It is a super-2 number, since 2×11130402000131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11130402000121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16022000 + ... + 16702253.

It is an arithmetic number, because the mean of its divisors is an integer number (2782608766128).

Almost surely, 2^{11130402000131} is an apocalyptic number.

11130402000131 is a deficient number, since it is larger than the sum of its proper divisors (33064381).

11130402000131 is an equidigital number, since it uses as much as digits as its factorization.

11130402000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33064380.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11130402000131 its reverse (13100020403111), we get a palindrome (24230422403242).

The spelling of 11130402000131 in words is "eleven trillion, one hundred thirty billion, four hundred two million, one hundred thirty-one", and thus it is an aban number.