13100020403111 has 4 divisors (see below), whose sum is σ = 13100043805224. Its totient is φ = 13099997001000.

The previous prime is 13100020403009. The next prime is 13100020403117. The reversal of 13100020403111 is 11130402000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100020403111 is a prime.

It is a super-2 number, since 2×13100020403111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13100020403111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100020403117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10840280 + ... + 11987981.

It is an arithmetic number, because the mean of its divisors is an integer number (3275010951306).

Almost surely, 2^{13100020403111} is an apocalyptic number.

13100020403111 is a deficient number, since it is larger than the sum of its proper divisors (23402113).

13100020403111 is an equidigital number, since it uses as much as digits as its factorization.

13100020403111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23402112.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13100020403111 its reverse (11130402000131), we get a palindrome (24230422403242).

The spelling of 13100020403111 in words is "thirteen trillion, one hundred billion, twenty million, four hundred three thousand, one hundred eleven".