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11133101101 is a prime number
BaseRepresentation
bin10100101111001010…
…11010010000101101
31001201212220010121211
422113211122100231
5140300033213401
65040420554421
7542613540463
oct122745322055
931655803554
1011133101101
1147a3388701
1221a8552a11
13108568a7b5
1477883a833
154525d1951
hex29795a42d

11133101101 has 2 divisors, whose sum is σ = 11133101102. Its totient is φ = 11133101100.

The previous prime is 11133101099. The next prime is 11133101113. The reversal of 11133101101 is 10110133111.

11133101101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10878698601 + 254402500 = 104301^2 + 15950^2 .

It is a cyclic number.

It is not a de Polignac number, because 11133101101 - 21 = 11133101099 is a prime.

Together with 11133101099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11103101101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566550550 + 5566550551.

It is an arithmetic number, because the mean of its divisors is an integer number (5566550551).

Almost surely, 211133101101 is an apocalyptic number.

It is an amenable number.

11133101101 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133101101 is an equidigital number, since it uses as much as digits as its factorization.

11133101101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 11133101101 its reverse (10110133111), we get a palindrome (21243234212).

The spelling of 11133101101 in words is "eleven billion, one hundred thirty-three million, one hundred one thousand, one hundred one".