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111332310407 is a prime number
BaseRepresentation
bin110011110101111101…
…1000011110110000111
3101122100221101100122222
41213223323003312013
53311002032413112
6123051221442555
711020630011233
oct1475373036607
9348327340588
10111332310407
114324120669a
12196b0b7045b
13a663538666
1455621155c3
152d6906b372
hex19ebec3d87

111332310407 has 2 divisors, whose sum is σ = 111332310408. Its totient is φ = 111332310406.

The previous prime is 111332310289. The next prime is 111332310409. The reversal of 111332310407 is 704013233111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111332310407 - 28 = 111332310151 is a prime.

Together with 111332310409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111332310409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55666155203 + 55666155204.

It is an arithmetic number, because the mean of its divisors is an integer number (55666155204).

Almost surely, 2111332310407 is an apocalyptic number.

111332310407 is a deficient number, since it is larger than the sum of its proper divisors (1).

111332310407 is an equidigital number, since it uses as much as digits as its factorization.

111332310407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 111332310407 its reverse (704013233111), we get a palindrome (815345543518).

The spelling of 111332310407 in words is "one hundred eleven billion, three hundred thirty-two million, three hundred ten thousand, four hundred seven".