11143311130 has 48 divisors (see below), whose sum is σ = 24351181056. Its totient is φ = 3595818240.

The previous prime is 11143311071. The next prime is 11143311131. The reversal of 11143311130 is 3111334111.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 11143311098 and 11143311107.

It is not an unprimeable number, because it can be changed into a prime (11143311131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 255186 + ... + 295645.

It is an arithmetic number, because the mean of its divisors is an integer number (507316272).

Almost surely, 2^11143311130 is an apocalyptic number.

11143311130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11143311130 is an abundant number, since it is smaller than the sum of its proper divisors (13207869926).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11143311130 is a wasteful number, since it uses less digits than its factorization.

11143311130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 550879 (or 550862 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11143311130 its reverse (3111334111), we get a palindrome (14254645241).

The spelling of 11143311130 in words is "eleven billion, one hundred forty-three million, three hundred eleven thousand, one hundred thirty".