1120134431440 has 160 divisors (see below), whose sum is σ = 2786185958400. Its totient is φ = 417564979200.

The previous prime is 1120134431363. The next prime is 1120134431447. The reversal of 1120134431440 is 441344310211.

It is a super-2 number, since 2×1120134431440² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1120134431399 and 1120134431408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1120134431447) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43150465 + ... + 43176415.

It is an arithmetic number, because the mean of its divisors is an integer number (17413662240).

Almost surely, 2^{1120134431440} is an apocalyptic number.

1120134431440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1120134431440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1393092979200).

1120134431440 is an abundant number, since it is smaller than the sum of its proper divisors (1666051526960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1120134431440 is a wasteful number, since it uses less digits than its factorization.

1120134431440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26445 (or 26439 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1120134431440 its reverse (441344310211), we get a palindrome (1561478741651).

The spelling of 1120134431440 in words is "one trillion, one hundred twenty billion, one hundred thirty-four million, four hundred thirty-one thousand, four hundred forty".