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112100112000112 = 247006257000007
BaseRepresentation
bin11001011111010001010111…
…010110101110010001110000
3112200220122222112210011121011
4121133101113112232101300
5104143122012133000422
61034230025220240304
732416652164135225
oct3137212726562160
9480818875704534
10112100112000112
113279a432864455
12106a5904840094
134a71cc25cab02
141d9796268794c
15ce5eab6a0077
hex65f4575ae470

112100112000112 has 10 divisors (see below), whose sum is σ = 217193967000248. Its totient is φ = 56050056000048.

The previous prime is 112100112000109. The next prime is 112100112000143. The reversal of 112100112000112 is 211000211001211.

It is a happy number.

It is a super-2 number, since 2×1121001120001122 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112100112000092 and 112100112000101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3503128499988 + ... + 3503128500019.

Almost surely, 2112100112000112 is an apocalyptic number.

It is an amenable number.

112100112000112 is a deficient number, since it is larger than the sum of its proper divisors (105093855000136).

112100112000112 is an equidigital number, since it uses as much as digits as its factorization.

112100112000112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7006257000015 (or 7006257000009 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 112100112000112 its reverse (211000211001211), we get a palindrome (323100323001323).

The spelling of 112100112000112 in words is "one hundred twelve trillion, one hundred billion, one hundred twelve million, one hundred twelve", and thus it is an aban number.

Divisors: 1 2 4 8 16 7006257000007 14012514000014 28025028000028 56050056000056 112100112000112