Base | Representation |
---|---|
bin | 10100111000011111… |
… | …01110100010111111 |
3 | 1001221100001012121021 |
4 | 22130033232202333 |
5 | 140430043144403 |
6 | 5052253045011 |
7 | 544553334610 |
oct | 123417564277 |
9 | 31840035537 |
10 | 11211303103 |
11 | 4833540a60 |
12 | 220a786767 |
13 | 109893b680 |
14 | 784d95c07 |
15 | 4593cc8bd |
hex | 29c3ee8bf |
11211303103 has 64 divisors (see below), whose sum is σ = 15899369472. Its totient is φ = 7619230080.
The previous prime is 11211303083. The next prime is 11211303121. The reversal of 11211303103 is 30130311211.
It is not a de Polignac number, because 11211303103 - 25 = 11211303071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11211303203) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1907976 + ... + 1913842.
It is an arithmetic number, because the mean of its divisors is an integer number (248427648).
Almost surely, 211211303103 is an apocalyptic number.
11211303103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11211303103 is a deficient number, since it is larger than the sum of its proper divisors (4688066369).
11211303103 is a wasteful number, since it uses less digits than its factorization.
11211303103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6004.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11211303103 its reverse (30130311211), we get a palindrome (41341614314).
The spelling of 11211303103 in words is "eleven billion, two hundred eleven million, three hundred three thousand, one hundred three".
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