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1121131201319 is a prime number
BaseRepresentation
bin10000010100001000101…
…000001000001100100111
310222011211120011000110122
4100110020220020030213
5121332034041420234
62215012432312155
7143666450655323
oct20241050101447
93864746130418
101121131201319
113a2518376338
121613486a265b
13819509395ac
143c397ad0983
151e26abb792e
hex10508a08327

1121131201319 has 2 divisors, whose sum is σ = 1121131201320. Its totient is φ = 1121131201318.

The previous prime is 1121131201243. The next prime is 1121131201321. The reversal of 1121131201319 is 9131021311211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1121131201319 - 216 = 1121131135783 is a prime.

It is a super-2 number, since 2×11211312013192 (a number of 25 digits) contains 22 as substring.

Together with 1121131201321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121131201339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560565600659 + 560565600660.

It is an arithmetic number, because the mean of its divisors is an integer number (560565600660).

Almost surely, 21121131201319 is an apocalyptic number.

1121131201319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121131201319 is an equidigital number, since it uses as much as digits as its factorization.

1121131201319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 26.

The spelling of 1121131201319 in words is "one trillion, one hundred twenty-one billion, one hundred thirty-one million, two hundred one thousand, three hundred nineteen".