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112113303120 = 243357132324799
BaseRepresentation
bin110100001101001111…
…0010011111001010000
3101201101100221220021000
41220122132103321100
53314102001144440
6123300521102000
711046162232020
oct1503236237120
9351340856230
10112113303120
1143602045015
121988a627900
13a759294c20
1455d7b33a80
152db28db730
hex1a1a793e50

112113303120 has 640 divisors, whose sum is σ = 495968256000. Its totient is φ = 22625298432.

The previous prime is 112113303119. The next prime is 112113303151. The reversal of 112113303120 is 21303311211.

112113303120 is a `hidden beast` number, since 1 + 1 + 21 + 1 + 330 + 312 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 112113303093 and 112113303102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 4508481 + ... + 4533279.

It is an arithmetic number, because the mean of its divisors is an integer number (774950400).

Almost surely, 2112113303120 is an apocalyptic number.

112113303120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112113303120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (247984128000).

112113303120 is an abundant number, since it is smaller than the sum of its proper divisors (383854952880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112113303120 is a wasteful number, since it uses less digits than its factorization.

112113303120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24864 (or 24852 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 112113303120 its reverse (21303311211), we get a palindrome (133416614331).

The spelling of 112113303120 in words is "one hundred twelve billion, one hundred thirteen million, three hundred three thousand, one hundred twenty".