Base | Representation |
---|---|
bin | 1010001100101001001110… |
… | …1000100101010101100000 |
3 | 1110200220000100201010222121 |
4 | 2203022103220211111200 |
5 | 2432200333413011000 |
6 | 35502513435314024 |
7 | 2235031163342230 |
oct | 243122350452540 |
9 | 43626010633877 |
10 | 11212341532000 |
11 | 3633144542834 |
12 | 131103a5ab914 |
13 | 63441c58778b |
14 | 2aa974779cc0 |
15 | 1469d3363b1a |
hex | a3293a25560 |
11212341532000 has 96 divisors (see below), whose sum is σ = 31484255100480. Its totient is φ = 3844231372800.
The previous prime is 11212341531959. The next prime is 11212341532061. The reversal of 11212341532000 is 23514321211.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 200192385 + ... + 200248384.
It is an arithmetic number, because the mean of its divisors is an integer number (327960990630).
Almost surely, 211212341532000 is an apocalyptic number.
11212341532000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11212341532000 is an abundant number, since it is smaller than the sum of its proper divisors (20271913568480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11212341532000 is an equidigital number, since it uses as much as digits as its factorization.
11212341532000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 400440801 (or 400440783 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11212341532000 its reverse (23514321211), we get a palindrome (11235855853211).
The spelling of 11212341532000 in words is "eleven trillion, two hundred twelve billion, three hundred forty-one million, five hundred thirty-two thousand".
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