Base | Representation |
---|---|
bin | 110100001101110011… |
… | …0000001010010110100 |
3 | 101201102200022221111220 |
4 | 1220123212001102310 |
5 | 3314121304220200 |
6 | 123302432030340 |
7 | 11046511064142 |
oct | 1503346012264 |
9 | 351380287456 |
10 | 112132101300 |
11 | 436117143aa |
12 | 198949923b0 |
13 | a7601472cb |
14 | 55da428592 |
15 | 2db43a14a0 |
hex | 1a1b9814b4 |
112132101300 has 144 divisors (see below), whose sum is σ = 332568839232. Its totient is φ = 29153254400.
The previous prime is 112132101287. The next prime is 112132101311. The reversal of 112132101300 is 3101231211.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 112132101300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 36369559 + ... + 36372641.
It is an arithmetic number, because the mean of its divisors is an integer number (2309505828).
Almost surely, 2112132101300 is an apocalyptic number.
112132101300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112132101300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166284419616).
112132101300 is an abundant number, since it is smaller than the sum of its proper divisors (220436737932).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112132101300 is a wasteful number, since it uses less digits than its factorization.
112132101300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6098 (or 6091 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 112132101300 its reverse (3101231211), we get a palindrome (115233332511).
The spelling of 112132101300 in words is "one hundred twelve billion, one hundred thirty-two million, one hundred one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •