Base | Representation |
---|---|
bin | 100001011110010… |
… | …1101011110001011 |
3 | 2220021112001000212 |
4 | 1002330231132023 |
5 | 4300020224042 |
6 | 303242151335 |
7 | 36556065032 |
oct | 10274553613 |
9 | 2807461025 |
10 | 1123211147 |
11 | 527029183 |
12 | 2741b254b |
13 | 14b9198a6 |
14 | a9261719 |
15 | 6891d482 |
hex | 42f2d78b |
1123211147 has 2 divisors, whose sum is σ = 1123211148. Its totient is φ = 1123211146.
The previous prime is 1123211129. The next prime is 1123211149. The reversal of 1123211147 is 7411123211.
It is a strong prime.
It is an emirp because it is prime and its reverse (7411123211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1123211147 is a prime.
Together with 1123211149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1123211149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561605573 + 561605574.
It is an arithmetic number, because the mean of its divisors is an integer number (561605574).
Almost surely, 21123211147 is an apocalyptic number.
1123211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123211147 is an equidigital number, since it uses as much as digits as its factorization.
1123211147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 336, while the sum is 23.
The square root of 1123211147 is about 33514.3424073933. The cubic root of 1123211147 is about 1039.4903651325.
Adding to 1123211147 its reverse (7411123211), we get a palindrome (8534334358).
The spelling of 1123211147 in words is "one billion, one hundred twenty-three million, two hundred eleven thousand, one hundred forty-seven".
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