1123413213130 has 128 divisors (see below), whose sum is σ = 2269979873280. Its totient is φ = 397653822720.

The previous prime is 1123413213121. The next prime is 1123413213137. The reversal of 1123413213130 is 313123143211.

It is a junction number, because it is equal to n+sod(n) for n = 1123413213095 and 1123413213104.

It is not an unprimeable number, because it can be changed into a prime (1123413213137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 73269565 + ... + 73284895.

It is an arithmetic number, because the mean of its divisors is an integer number (17734217760).

Almost surely, 2^{1123413213130} is an apocalyptic number.

1123413213130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1123413213130 is an abundant number, since it is smaller than the sum of its proper divisors (1146566660150).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1123413213130 is a wasteful number, since it uses less digits than its factorization.

1123413213130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15644.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1123413213130 its reverse (313123143211), we get a palindrome (1436536356341).

The spelling of 1123413213130 in words is "one trillion, one hundred twenty-three billion, four hundred thirteen million, two hundred thirteen thousand, one hundred thirty".