Base | Representation |
---|---|
bin | 110100010100000101… |
… | …1000010110011011000 |
3 | 101201222101102111010121 |
4 | 1220220023002303120 |
5 | 3320034320232100 |
6 | 123335411123024 |
7 | 11054652610111 |
oct | 1505013026330 |
9 | 351871374117 |
10 | 112343133400 |
11 | 4370a8519a3 |
12 | 199335a3474 |
13 | a794a94b84 |
14 | 561a47d208 |
15 | 2dc7b8951a |
hex | 1a282c2cd8 |
112343133400 has 48 divisors (see below), whose sum is σ = 261220881240. Its totient is φ = 44933280000.
The previous prime is 112343133391. The next prime is 112343133407. The reversal of 112343133400 is 4331343211.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112343133407) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3467275 + ... + 3499525.
Almost surely, 2112343133400 is an apocalyptic number.
112343133400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
112343133400 is an abundant number, since it is smaller than the sum of its proper divisors (148877747840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112343133400 is a wasteful number, since it uses less digits than its factorization.
112343133400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49684 (or 49675 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 112343133400 its reverse (4331343211), we get a palindrome (116674476611).
The spelling of 112343133400 in words is "one hundred twelve billion, three hundred forty-three million, one hundred thirty-three thousand, four hundred".
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