113023110040 has 16 divisors (see below), whose sum is σ = 254301997680. Its totient is φ = 45209244000.

The previous prime is 113023110037. The next prime is 113023110059. The reversal of 113023110040 is 40011320311.

It is a super-2 number, since 2×113023110040² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113023109996 and 113023110023.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1412788836 + ... + 1412788915.

It is an arithmetic number, because the mean of its divisors is an integer number (15893874855).

Almost surely, 2^113023110040 is an apocalyptic number.

113023110040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113023110040 is an abundant number, since it is smaller than the sum of its proper divisors (141278887640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113023110040 is a wasteful number, since it uses less digits than its factorization.

113023110040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2825577762 (or 2825577758 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 113023110040 its reverse (40011320311), we get a palindrome (153034430351).

The spelling of 113023110040 in words is "one hundred thirteen billion, twenty-three million, one hundred ten thousand, forty".