Base | Representation |
---|---|
bin | 11001101100110011101100… |
… | …010001010001110101111000 |
3 | 112211012121000120111000102101 |
4 | 121230303230101101311320 |
5 | 104303342100232022130 |
6 | 1040221225205113144 |
7 | 32544112531633216 |
oct | 3154635421216570 |
9 | 484177016430371 |
10 | 113030323314040 |
11 | 330189888a8590 |
12 | 1081604a6b87b4 |
13 | 4b0b938167c22 |
14 | 1dca9a81a3cb6 |
15 | d102a11471ca |
hex | 66ccec451d78 |
113030323314040 has 32 divisors (see below), whose sum is σ = 277438066317360. Its totient is φ = 41101935750400.
The previous prime is 113030323313863. The next prime is 113030323314061. The reversal of 113030323314040 is 40413323030311.
It is a super-2 number, since 2×1130303233140402 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128443548781 + ... + 128443549660.
Almost surely, 2113030323314040 is an apocalyptic number.
113030323314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113030323314040 is an abundant number, since it is smaller than the sum of its proper divisors (164407743003320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113030323314040 is a wasteful number, since it uses less digits than its factorization.
113030323314040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256887098463 (or 256887098459 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 113030323314040 its reverse (40413323030311), we get a palindrome (153443646344351).
The spelling of 113030323314040 in words is "one hundred thirteen trillion, thirty billion, three hundred twenty-three million, three hundred fourteen thousand, forty".
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