Base | Representation |
---|---|
bin | 1010010001111011011000… |
… | …0010110000110000101100 |
3 | 1111000120022101111020211110 |
4 | 2210132312002300300230 |
5 | 2440142233430224400 |
6 | 40012324541552020 |
7 | 2244423452252535 |
oct | 244366602606054 |
9 | 44016271436743 |
10 | 11303113133100 |
11 | 3668694768188 |
12 | 1326751875610 |
13 | 63cb571c8649 |
14 | 2b1105d2d68c |
15 | 149047307e50 |
hex | a47b60b0c2c |
11303113133100 has 72 divisors (see below), whose sum is σ = 32709096445648. Its totient is φ = 3013663737600.
The previous prime is 11303113133089. The next prime is 11303113133129. The reversal of 11303113133100 is 133131130311.
It is a super-2 number, since 2×113031131331002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1309411 + ... + 4931610.
Almost surely, 211303113133100 is an apocalyptic number.
11303113133100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11303113133100 is an abundant number, since it is smaller than the sum of its proper divisors (21405983312548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11303113133100 is a wasteful number, since it uses less digits than its factorization.
11303113133100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6247075 (or 6247068 counting only the distinct ones).
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 11303113133100 its reverse (133131130311), we get a palindrome (11436244263411).
The spelling of 11303113133100 in words is "eleven trillion, three hundred three billion, one hundred thirteen million, one hundred thirty-three thousand, one hundred".
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