Base | Representation |
---|---|
bin | 11001101100110100101000… |
… | …010110100001010111010100 |
3 | 112211012200121211020002102121 |
4 | 121230310220112201113110 |
5 | 104303401131304240200 |
6 | 1040221513214145324 |
7 | 32544146521564000 |
oct | 3154645026412724 |
9 | 484180554202377 |
10 | 113031331321300 |
11 | 330193558a0337 |
12 | 108162901b2244 |
13 | 4b0ba68c49922 |
14 | 1dcaa61dd7700 |
15 | d1030e8aae1a |
hex | 66cd285a15d4 |
113031331321300 has 72 divisors (see below), whose sum is σ = 286038471185600. Its totient is φ = 38753599298400.
The previous prime is 113031331321247. The next prime is 113031331321369. The reversal of 113031331321300 is 3123133130311.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1647652746 + ... + 1647721345.
Almost surely, 2113031331321300 is an apocalyptic number.
113031331321300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113031331321300 is an abundant number, since it is smaller than the sum of its proper divisors (173007139864300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113031331321300 is a wasteful number, since it uses less digits than its factorization.
113031331321300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3295374126 (or 3295374105 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 113031331321300 its reverse (3123133130311), we get a palindrome (116154464451611).
The spelling of 113031331321300 in words is "one hundred thirteen trillion, thirty-one billion, three hundred thirty-one million, three hundred twenty-one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •