1131011311320 has 288 divisors, whose sum is σ = 4215997749600. Its totient is φ = 262263260160.

The previous prime is 1131011311303. The next prime is 1131011311333. The reversal of 1131011311320 is 231131101311.

1131011311320 is a `hidden beast` number, since 1 + 1 + 31 + 0 + 1 + 1 + 311 + 320 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1131011311293 and 1131011311302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 437436 + ... + 1566324.

It is an arithmetic number, because the mean of its divisors is an integer number (14638881075).

Almost surely, 2^{1131011311320} is an apocalyptic number.

1131011311320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131011311320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2107998874800).

1131011311320 is an abundant number, since it is smaller than the sum of its proper divisors (3084986438280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131011311320 is a wasteful number, since it uses less digits than its factorization.

1131011311320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1128951 (or 1128933 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 1131011311320 its reverse (231131101311), we get a palindrome (1362142412631).

The spelling of 1131011311320 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred eleven thousand, three hundred twenty".