113101313000100 has 72 divisors (see below), whose sum is σ = 327268050983328. Its totient is φ = 30157746259200.

The previous prime is 113101313000077. The next prime is 113101313000101. The reversal of 113101313000100 is 1000313101311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 113101313000100.

It is not an unprimeable number, because it can be changed into a prime (113101313000101) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12792321 + ... + 19744520.

Almost surely, 2^{113101313000100} is an apocalyptic number.

113101313000100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113101313000100 is an abundant number, since it is smaller than the sum of its proper divisors (214166737983228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113101313000100 is a wasteful number, since it uses less digits than its factorization.

113101313000100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32548445 (or 32548438 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 113101313000100 its reverse (1000313101311), we get a palindrome (114101626101411).

The spelling of 113101313000100 in words is "one hundred thirteen trillion, one hundred one billion, three hundred thirteen million, one hundred", and thus it is an aban number.