Base | Representation |
---|---|
bin | 10000011101010110000… |
… | …111110111001010110000 |
3 | 11000010100211010002212121 |
4 | 100131112013313022300 |
5 | 122012312423103100 |
6 | 2223330051404024 |
7 | 144466522300405 |
oct | 20352607671260 |
9 | 4003324102777 |
10 | 1131021300400 |
11 | 3a6733047142 |
12 | 1632488b3614 |
13 | 82868927824 |
14 | 3ca554062ac |
15 | 1e6490b751a |
hex | 107561f72b0 |
1131021300400 has 60 divisors (see below), whose sum is σ = 2717858784744. Its totient is φ = 452311936000.
The previous prime is 1131021300371. The next prime is 1131021300439. The reversal of 1131021300400 is 40031201311.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1588935 + ... + 2187865.
Almost surely, 21131021300400 is an apocalyptic number.
1131021300400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131021300400 is an abundant number, since it is smaller than the sum of its proper divisors (1586837484344).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131021300400 is a wasteful number, since it uses less digits than its factorization.
1131021300400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 603670 (or 603659 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1131021300400 its reverse (40031201311), we get a palindrome (1171052501711).
The spelling of 1131021300400 in words is "one trillion, one hundred thirty-one billion, twenty-one million, three hundred thousand, four hundred".
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