11310402411311 has 2 divisors, whose sum is σ = 11310402411312. Its totient is φ = 11310402411310.

The previous prime is 11310402411307. The next prime is 11310402411313. The reversal of 11310402411311 is 11311420401311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11310402411311 - 2² = 11310402411307 is a prime.

Together with 11310402411313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310402411313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655201205655 + 5655201205656.

It is an arithmetic number, because the mean of its divisors is an integer number (5655201205656).

Almost surely, 2^{11310402411311} is an apocalyptic number.

11310402411311 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310402411311 is an equidigital number, since it uses as much as digits as its factorization.

11310402411311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 11310402411311 its reverse (11311420401311), we get a palindrome (22621822812622).

The spelling of 11310402411311 in words is "eleven trillion, three hundred ten billion, four hundred two million, four hundred eleven thousand, three hundred eleven".