Base | Representation |
---|---|
bin | 10000011101011100000… |
… | …101000001101011001100 |
3 | 11000010121210010120012122 |
4 | 100131130011001223030 |
5 | 122013014013022200 |
6 | 2223344021152112 |
7 | 144502144510151 |
oct | 20353405015314 |
9 | 4003553116178 |
10 | 1131121220300 |
11 | 3a6784493475 |
12 | 16327625b638 |
13 | 82883540a26 |
14 | 3ca647b6228 |
15 | 1e652c53385 |
hex | 1075c141acc |
1131121220300 has 36 divisors (see below), whose sum is σ = 2533711540416. Its totient is φ = 437853374400.
The previous prime is 1131121220287. The next prime is 1131121220311. The reversal of 1131121220300 is 30221211311.
It is a super-2 number, since 2×11311212203002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 182435807 + ... + 182442006.
Almost surely, 21131121220300 is an apocalyptic number.
1131121220300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131121220300 is an abundant number, since it is smaller than the sum of its proper divisors (1402590320116).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131121220300 is a wasteful number, since it uses less digits than its factorization.
1131121220300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 364877858 (or 364877851 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1131121220300 its reverse (30221211311), we get a palindrome (1161342431611).
The spelling of 1131121220300 in words is "one trillion, one hundred thirty-one billion, one hundred twenty-one million, two hundred twenty thousand, three hundred".
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