Base | Representation |
---|---|
bin | 10101000100100000… |
… | …10110110111000000 |
3 | 1002012100202211012002 |
4 | 22202100112313000 |
5 | 141131401202040 |
6 | 5110254123132 |
7 | 550216350164 |
oct | 124220266700 |
9 | 32170684162 |
10 | 11312131520 |
11 | 4885448928 |
12 | 22384b04a8 |
13 | 10b37b2261 |
14 | 794520ca4 |
15 | 463197a15 |
hex | 2a2416dc0 |
11312131520 has 28 divisors (see below), whose sum is σ = 26937013944. Its totient is φ = 4524852480.
The previous prime is 11312131463. The next prime is 11312131547. The reversal of 11312131520 is 2513121311.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 11312131492 and 11312131501.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17674886 + ... + 17675525.
Almost surely, 211312131520 is an apocalyptic number.
11312131520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11312131520 is an abundant number, since it is smaller than the sum of its proper divisors (15624882424).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312131520 is an equidigital number, since it uses as much as digits as its factorization.
11312131520 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35350428 (or 35350418 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 11312131520 its reverse (2513121311), we get a palindrome (13825252831).
The spelling of 11312131520 in words is "eleven billion, three hundred twelve million, one hundred thirty-one thousand, five hundred twenty".
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