Base | Representation |
---|---|
bin | 110100101011010011… |
… | …0111111010111100101 |
3 | 101210222200101202002200 |
4 | 1221112212333113211 |
5 | 3323133241230201 |
6 | 123545001325113 |
7 | 11113162634211 |
oct | 1512646772745 |
9 | 353880352080 |
10 | 113122211301 |
11 | 43a7a5a2730 |
12 | 19b10496799 |
13 | a88a300a08 |
14 | 5691b1d941 |
15 | 2e2127c386 |
hex | 1a569bf5e5 |
113122211301 has 24 divisors (see below), whose sum is σ = 178263768384. Its totient is φ = 68554844160.
The previous prime is 113122211297. The next prime is 113122211459. The reversal of 113122211301 is 103112221311.
113122211301 is a `hidden beast` number, since 1 + 1 + 312 + 221 + 130 + 1 = 666.
It is not a de Polignac number, because 113122211301 - 22 = 113122211297 is a prime.
It is a super-2 number, since 2×1131222113012 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113122210301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3048280 + ... + 3085166.
It is an arithmetic number, because the mean of its divisors is an integer number (7427657016).
Almost surely, 2113122211301 is an apocalyptic number.
113122211301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
113122211301 is a deficient number, since it is larger than the sum of its proper divisors (65141557083).
113122211301 is a wasteful number, since it uses less digits than its factorization.
113122211301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67881 (or 67878 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 113122211301 its reverse (103112221311), we get a palindrome (216234432612).
It can be divided in two parts, 113122 and 211301, that added together give a palindrome (324423).
The spelling of 113122211301 in words is "one hundred thirteen billion, one hundred twenty-two million, two hundred eleven thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •