Base | Representation |
---|---|
bin | 1010010010011101100110… |
… | …1100011101011100111000 |
3 | 1111001110000201110110210021 |
4 | 2210213121230131130320 |
5 | 2440320043101414313 |
6 | 40020444402100224 |
7 | 2245200240454240 |
oct | 244473154353470 |
9 | 44043021413707 |
10 | 11312301201208 |
11 | 367157a1317a7 |
12 | 132849694a674 |
13 | 64098c915c37 |
14 | 2b17382dcb20 |
15 | 1493d3c8378d |
hex | a49d9b1d738 |
11312301201208 has 64 divisors (see below), whose sum is σ = 25731217909440. Its totient is φ = 4551451305984.
The previous prime is 11312301201199. The next prime is 11312301201209. The reversal of 11312301201208 is 80210210321311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312301201209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14587635 + ... + 15343522.
It is an arithmetic number, because the mean of its divisors is an integer number (402050279835).
Almost surely, 211312301201208 is an apocalyptic number.
It is an amenable number.
11312301201208 is an abundant number, since it is smaller than the sum of its proper divisors (14418916708232).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312301201208 is a wasteful number, since it uses less digits than its factorization.
11312301201208 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29931584 (or 29931580 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 11312301201208 its reverse (80210210321311), we get a palindrome (91522511522519).
The spelling of 11312301201208 in words is "eleven trillion, three hundred twelve billion, three hundred one million, two hundred one thousand, two hundred eight".
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