113130041242240 has 1024 divisors, whose sum is σ = 323336344320000. Its totient is φ = 37408186368000.

The previous prime is 113130041242223. The next prime is 113130041242243. The reversal of 113130041242240 is 42242140031311.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 113130041242199 and 113130041242208.

It is not an unprimeable number, because it can be changed into a prime (113130041242243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 86557031667 + ... + 86557032973.

It is an arithmetic number, because the mean of its divisors is an integer number (315758148750).

Almost surely, 2^{113130041242240} is an apocalyptic number.

113130041242240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113130041242240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161668172160000).

113130041242240 is an abundant number, since it is smaller than the sum of its proper divisors (210206303077760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113130041242240 is a wasteful number, since it uses less digits than its factorization.

113130041242240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1649 (or 1637 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 113130041242240 its reverse (42242140031311), we get a palindrome (155372181273551).

The spelling of 113130041242240 in words is "one hundred thirteen trillion, one hundred thirty billion, forty-one million, two hundred forty-two thousand, two hundred forty".