1131302015 has 4 divisors (see below), whose sum is σ = 1357562424. Its totient is φ = 905041608.

The previous prime is 1131301993. The next prime is 1131302027. The reversal of 1131302015 is 5102031311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5102031311 = 13 ⋅392463947.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131302015 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131301984 and 1131302002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113130197 + ... + 113130206.

It is an arithmetic number, because the mean of its divisors is an integer number (339390606).

Almost surely, 2^1131302015 is an apocalyptic number.

1131302015 is a deficient number, since it is larger than the sum of its proper divisors (226260409).

1131302015 is an equidigital number, since it uses as much as digits as its factorization.

1131302015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 226260408.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 1131302015 is about 33634.8333576963. The cubic root of 1131302015 is about 1041.9803289943.

Adding to 1131302015 its reverse (5102031311), we get a palindrome (6233333326).

The spelling of 1131302015 in words is "one billion, one hundred thirty-one million, three hundred two thousand, fifteen".