Base | Representation |
---|---|
bin | 10000011101100111011… |
… | …100111000000111111101 |
3 | 11000011010002011021221202 |
4 | 100131213130320013331 |
5 | 122013411334201023 |
6 | 2223414554505245 |
7 | 144506652344315 |
oct | 20354734700775 |
9 | 4004102137852 |
10 | 1131312022013 |
11 | 3a6872163638 |
12 | 16330a135225 |
13 | 828b3c27354 |
14 | 3ca81c82445 |
15 | 1e664892128 |
hex | 107677381fd |
1131312022013 has 4 divisors (see below), whose sum is σ = 1132217797500. Its totient is φ = 1130406246528.
The previous prime is 1131312021989. The next prime is 1131312022067. The reversal of 1131312022013 is 3102202131311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 904528438489 + 226783583524 = 951067^2 + 476218^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131312022013 - 28 = 1131312021757 is a prime.
It is a super-2 number, since 2×11313120220132 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131312022613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 452885870 + ... + 452888367.
It is an arithmetic number, because the mean of its divisors is an integer number (283054449375).
Almost surely, 21131312022013 is an apocalyptic number.
It is an amenable number.
1131312022013 is a deficient number, since it is larger than the sum of its proper divisors (905775487).
1131312022013 is an equidigital number, since it uses as much as digits as its factorization.
1131312022013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 905775486.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1131312022013 its reverse (3102202131311), we get a palindrome (4233514153324).
The spelling of 1131312022013 in words is "one trillion, one hundred thirty-one billion, three hundred twelve million, twenty-two thousand, thirteen".
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