Base | Representation |
---|---|
bin | 10101000100101000… |
… | …10010010110110100 |
3 | 1002012102201011021010 |
4 | 22202110102112310 |
5 | 141132132133102 |
6 | 5110332152220 |
7 | 550231200402 |
oct | 124224222664 |
9 | 32172634233 |
10 | 11313161652 |
11 | 4885a91881 |
12 | 2238908670 |
13 | 10b3a830c0 |
14 | 79470c472 |
15 | 4632ecd6c |
hex | 2a25125b4 |
11313161652 has 48 divisors (see below), whose sum is σ = 29121325632. Its totient is φ = 3396069120.
The previous prime is 11313161633. The next prime is 11313161719. The reversal of 11313161652 is 25616131311.
It is a super-4 number, since 4×113131616524 (a number of 41 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 877998 + ... + 890789.
It is an arithmetic number, because the mean of its divisors is an integer number (606694284).
Almost surely, 211313161652 is an apocalyptic number.
11313161652 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11313161652 is an abundant number, since it is smaller than the sum of its proper divisors (17808163980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313161652 is a wasteful number, since it uses less digits than its factorization.
11313161652 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1768848 (or 1768846 counting only the distinct ones).
The product of its digits is 3240, while the sum is 30.
Adding to 11313161652 its reverse (25616131311), we get a palindrome (36929292963).
The spelling of 11313161652 in words is "eleven billion, three hundred thirteen million, one hundred sixty-one thousand, six hundred fifty-two".
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