Base | Representation |
---|---|
bin | 110100101011110111… |
… | …1001011001111011100 |
3 | 101211001000000010120111 |
4 | 1221113233023033130 |
5 | 3323203112244200 |
6 | 123550515055404 |
7 | 11113512526255 |
oct | 1512757131734 |
9 | 354030003514 |
10 | 113141134300 |
11 | 43a8a247877 |
12 | 19b168a1564 |
13 | a8911c7b5c |
14 | 5694447b2c |
15 | 2e22c690ba |
hex | 1a57bcb3dc |
113141134300 has 36 divisors (see below), whose sum is σ = 248274890640. Its totient is φ = 44747950720.
The previous prime is 113141134289. The next prime is 113141134307. The reversal of 113141134300 is 3431141311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113141134307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6347344 + ... + 6365143.
It is an arithmetic number, because the mean of its divisors is an integer number (6896524740).
Almost surely, 2113141134300 is an apocalyptic number.
113141134300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113141134300 is an abundant number, since it is smaller than the sum of its proper divisors (135133756340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113141134300 is a wasteful number, since it uses less digits than its factorization.
113141134300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12712590 (or 12712583 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 113141134300 its reverse (3431141311), we get a palindrome (116572275611).
The spelling of 113141134300 in words is "one hundred thirteen billion, one hundred forty-one million, one hundred thirty-four thousand, three hundred".
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