Base | Representation |
---|---|
bin | 10101000100101111… |
… | …11111011010011011 |
3 | 1002012111112111012110 |
4 | 22202113333122123 |
5 | 141132404221020 |
6 | 5110405043403 |
7 | 550242353301 |
oct | 124227773233 |
9 | 32174474173 |
10 | 11314132635 |
11 | 4886595343 |
12 | 22390b6563 |
13 | 10b4033050 |
14 | 7948c2271 |
15 | 4634408e0 |
hex | 2a25ff69b |
11314132635 has 32 divisors (see below), whose sum is σ = 20521186560. Its totient is φ = 5276873088.
The previous prime is 11314132631. The next prime is 11314132639. The reversal of 11314132635 is 53623141311.
It is an interprime number because it is at equal distance from previous prime (11314132631) and next prime (11314132639).
It is not a de Polignac number, because 11314132635 - 22 = 11314132631 is a prime.
It is a super-3 number, since 3×113141326353 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11314132631) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1523169 + ... + 1530578.
It is an arithmetic number, because the mean of its divisors is an integer number (641287080).
Almost surely, 211314132635 is an apocalyptic number.
11314132635 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11314132635 is a deficient number, since it is larger than the sum of its proper divisors (9207053925).
11314132635 is a wasteful number, since it uses less digits than its factorization.
11314132635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3053787.
The product of its digits is 6480, while the sum is 30.
Adding to 11314132635 its reverse (53623141311), we get a palindrome (64937273946).
The spelling of 11314132635 in words is "eleven billion, three hundred fourteen million, one hundred thirty-two thousand, six hundred thirty-five".
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