Base | Representation |
---|---|
bin | 11001101110011011100001… |
… | …011111001010011101100000 |
3 | 112211121020210101021102102022 |
4 | 121232123201133022131200 |
5 | 104312203412224213034 |
6 | 1040344344121041012 |
7 | 32555140364222132 |
oct | 3156334137123540 |
9 | 484536711242368 |
10 | 113141811554144 |
11 | 3306119a02649a |
12 | 10833783926168 |
13 | 4b192c4a9a479 |
14 | 1dd2142ca9052 |
15 | d13128c14b2e |
hex | 66e6e17ca760 |
113141811554144 has 96 divisors (see below), whose sum is σ = 225109083981600. Its totient is φ = 55974084526080.
The previous prime is 113141811554117. The next prime is 113141811554269. The reversal of 113141811554144 is 441455118141311.
It is a super-3 number, since 3×1131418115541443 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113141811554095 and 113141811554104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10745726672 + ... + 10745737200.
It is an arithmetic number, because the mean of its divisors is an integer number (2344886291475).
Almost surely, 2113141811554144 is an apocalyptic number.
It is an amenable number.
113141811554144 is a deficient number, since it is larger than the sum of its proper divisors (111967272427456).
113141811554144 is a wasteful number, since it uses less digits than its factorization.
113141811554144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18616 (or 18608 counting only the distinct ones).
The product of its digits is 153600, while the sum is 44.
Adding to 113141811554144 its reverse (441455118141311), we get a palindrome (554596929695455).
The spelling of 113141811554144 in words is "one hundred thirteen trillion, one hundred forty-one billion, eight hundred eleven million, five hundred fifty-four thousand, one hundred forty-four".
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