| Base | Representation |
|---|---|
| bin | 1010010010101000110100… |
| … | …0010111111100111110000 |
| 3 | 1111001201210102110222022002 |
| 4 | 2210222031002333213300 |
| 5 | 2440342223404330000 |
| 6 | 40022103132033132 |
| 7 | 2245334636003030 |
| oct | 244521502774760 |
| 9 | 44051712428262 |
| 10 | 11315310230000 |
| 11 | 36728836a9657 |
| 12 | 1328b966027a8 |
| 13 | 64104c13bc4a |
| 14 | 2b1941bb58c0 |
| 15 | 14950d00c8d5 |
| hex | a4a8d0bf9f0 |
11315310230000 has 400 divisors, whose sum is σ = 32763084456960. Its totient is φ = 3700333824000.
The previous prime is 11315310229997. The next prime is 11315310230009. The reversal of 11315310230000 is 3201351311.
11315310230000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (400).
It is a super-2 number, since 2×113153102300002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11315310230009) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 577980212 + ... + 577999788.
Almost surely, 211315310230000 is an apocalyptic number.
11315310230000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11315310230000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16381542228480).
11315310230000 is an abundant number, since it is smaller than the sum of its proper divisors (21447774226960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11315310230000 is a wasteful number, since it uses less digits than its factorization.
11315310230000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19994 (or 19973 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 11315310230000 its reverse (3201351311), we get a palindrome (11318511581311).
The spelling of 11315310230000 in words is "eleven trillion, three hundred fifteen billion, three hundred ten million, two hundred thirty thousand".
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