Base | Representation |
---|---|
bin | 110100101101101001… |
… | …1111011110011000111 |
3 | 101211012011211210211021 |
4 | 1221123103323303013 |
5 | 3323313440231043 |
6 | 124000500252011 |
7 | 11115141330262 |
oct | 1513323736307 |
9 | 354164753737 |
10 | 113201102023 |
11 | 44010086479 |
12 | 19b329a1007 |
13 | a8a0763209 |
14 | 569c3b7cd9 |
15 | 2e281623ed |
hex | 1a5b4fbcc7 |
113201102023 has 2 divisors, whose sum is σ = 113201102024. Its totient is φ = 113201102022.
The previous prime is 113201102011. The next prime is 113201102039. The reversal of 113201102023 is 320201102311.
It is an a-pointer prime, because the next prime (113201102039) can be obtained adding 113201102023 to its sum of digits (16).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113201102023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113201101988 and 113201102006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113201102093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600551011 + 56600551012.
It is an arithmetic number, because the mean of its divisors is an integer number (56600551012).
Almost surely, 2113201102023 is an apocalyptic number.
113201102023 is a deficient number, since it is larger than the sum of its proper divisors (1).
113201102023 is an equidigital number, since it uses as much as digits as its factorization.
113201102023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 113201102023 its reverse (320201102311), we get a palindrome (433402204334).
The spelling of 113201102023 in words is "one hundred thirteen billion, two hundred one million, one hundred two thousand, twenty-three".
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