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11320201202310 = 2325711132347116239
BaseRepresentation
bin1010010010111011000010…
…0100100100101010000110
31111002012102021201002222200
42210232300210210222012
52440432233001433220
640024232330335330
72245600065405360
oct244566044445206
944065367632880
1011320201202310
113674963509530
121329b2058a546
1364164b515bc0
142b1c875b5d30
151496e75c9890
hexa4bb0924a86

11320201202310 has 768 divisors, whose sum is σ = 42113681326080. Its totient is φ = 2032695751680.

The previous prime is 11320201202291. The next prime is 11320201202381. The reversal of 11320201202310 is 1320210202311.

11320201202310 is a `hidden beast` number, since 1 + 1 + 320 + 20 + 12 + 0 + 2 + 310 = 666.

It is a super-2 number, since 2×113202012023102 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 97329171 + ... + 97445409.

It is an arithmetic number, because the mean of its divisors is an integer number (54835522560).

Almost surely, 211320201202310 is an apocalyptic number.

11320201202310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11320201202310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21056840663040).

11320201202310 is an abundant number, since it is smaller than the sum of its proper divisors (30793480123770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11320201202310 is a wasteful number, since it uses less digits than its factorization.

11320201202310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116353 (or 116350 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11320201202310 its reverse (1320210202311), we get a palindrome (12640411404621).

Subtracting from 11320201202310 its reverse (1320210202311), we obtain a palindrome (9999990999999).

It can be divided in two parts, 11320201 and 202310, that added together give a palindrome (11522511).

The spelling of 11320201202310 in words is "eleven trillion, three hundred twenty billion, two hundred one million, two hundred two thousand, three hundred ten".