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11322013110 = 2357310514919
BaseRepresentation
bin10101000101101100…
…00011010110110110
31002020001100212011220
422202312003112312
5141141413404420
65111250011210
7550366344402
oct124266032666
932201325156
1011322013110
11488aa88031
12223b876b06
1310b5861c55
14795974102
15463e9a840
hex2a2d835b6

11322013110 has 64 divisors (see below), whose sum is σ = 27576875520. Its totient is φ = 2974406400.

The previous prime is 11322013067. The next prime is 11322013121. The reversal of 11322013110 is 1131022311.

It is a happy number.

11322013110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11322013110.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2299231 + ... + 2304149.

It is an arithmetic number, because the mean of its divisors is an integer number (430888680).

Almost surely, 211322013110 is an apocalyptic number.

11322013110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11322013110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13788437760).

11322013110 is an abundant number, since it is smaller than the sum of its proper divisors (16254862410).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11322013110 is a wasteful number, since it uses less digits than its factorization.

11322013110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6053.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11322013110 its reverse (1131022311), we get a palindrome (12453035421).

It can be divided in two parts, 1132201 and 3110, that added together give a palindrome (1135311).

The spelling of 11322013110 in words is "eleven billion, three hundred twenty-two million, thirteen thousand, one hundred ten".

Divisors: 1 2 3 5 6 10 15 30 73 146 219 365 438 730 1051 1095 2102 2190 3153 4919 5255 6306 9838 10510 14757 15765 24595 29514 31530 49190 73785 76723 147570 153446 230169 359087 383615 460338 718174 767230 1077261 1150845 1795435 2154522 2301690 3590870 5169869 5386305 10339738 10772610 15509607 25849345 31019214 51698690 77548035 155096070 377400437 754800874 1132201311 1887002185 2264402622 3774004370 5661006555 11322013110