Base | Representation |
---|---|
bin | 10000011110011110010… |
… | …111010100011110000010 |
3 | 11000020111021201200101221 |
4 | 100132132113110132002 |
5 | 122022303211442010 |
6 | 2224050225145254 |
7 | 144541540234324 |
oct | 20363627243602 |
9 | 4006437650357 |
10 | 1132233312130 |
11 | 3a71a5207528 |
12 | 16352678b22a |
13 | 829cca6642b |
14 | 3cb2c381614 |
15 | 1e6ba6c6dda |
hex | 1079e5d4782 |
1132233312130 has 128 divisors (see below), whose sum is σ = 2212927672320. Its totient is φ = 415863275520.
The previous prime is 1132233312127. The next prime is 1132233312131. The reversal of 1132233312130 is 312133322311.
It is a junction number, because it is equal to n+sod(n) for n = 1132233312095 and 1132233312104.
It is not an unprimeable number, because it can be changed into a prime (1132233312131) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 492917142 + ... + 492919438.
It is an arithmetic number, because the mean of its divisors is an integer number (17288497440).
Almost surely, 21132233312130 is an apocalyptic number.
1132233312130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1132233312130 is a deficient number, since it is larger than the sum of its proper divisors (1080694360190).
1132233312130 is a wasteful number, since it uses less digits than its factorization.
1132233312130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2884.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1132233312130 its reverse (312133322311), we get a palindrome (1444366634441).
The spelling of 1132233312130 in words is "one trillion, one hundred thirty-two billion, two hundred thirty-three million, three hundred twelve thousand, one hundred thirty".
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