Base | Representation |
---|---|
bin | 10101000110101001… |
… | …11100101111000111 |
3 | 1002020121121100101122 |
4 | 22203110330233013 |
5 | 141201002044310 |
6 | 5112135344155 |
7 | 550525236554 |
oct | 124324745707 |
9 | 32217540348 |
10 | 11330112455 |
11 | 489460a202 |
12 | 224252205b |
13 | 10b743966c |
14 | 796a81a2b |
15 | 464a4a555 |
hex | 2a353cbc7 |
11330112455 has 32 divisors (see below), whose sum is σ = 14399078400. Its totient is φ = 8541067392.
The previous prime is 11330112421. The next prime is 11330112463. The reversal of 11330112455 is 55421103311.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11330112455 is a prime.
It is a super-2 number, since 2×113301124552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5059226 + ... + 5061464.
It is an arithmetic number, because the mean of its divisors is an integer number (449971200).
Almost surely, 211330112455 is an apocalyptic number.
11330112455 is a deficient number, since it is larger than the sum of its proper divisors (3068965945).
11330112455 is a wasteful number, since it uses less digits than its factorization.
11330112455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2903.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 11330112455 its reverse (55421103311), we get a palindrome (66751215766).
The spelling of 11330112455 in words is "eleven billion, three hundred thirty million, one hundred twelve thousand, four hundred fifty-five".
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