Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0010110111111000111100 |
3 | 1111010020122000021002210110 |
4 | 2210320330002313320330 |
5 | 2441122124031104040 |
6 | 40033241052310020 |
7 | 2246434664203305 |
oct | 244707402677074 |
9 | 44106560232713 |
10 | 11331131113020 |
11 | 3679562125194 |
12 | 1330070a72310 |
13 | 6426a0a701a4 |
14 | 2b260303d7ac |
15 | 149b36e21980 |
hex | a4e3c0b7e3c |
11331131113020 has 48 divisors (see below), whose sum is σ = 31821313069728. Its totient is φ = 3012668682240.
The previous prime is 11331131113013. The next prime is 11331131113051. The reversal of 11331131113020 is 2031113113311.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280175901 + ... + 280216340.
It is an arithmetic number, because the mean of its divisors is an integer number (662944022286).
Almost surely, 211331131113020 is an apocalyptic number.
11331131113020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11331131113020 is an abundant number, since it is smaller than the sum of its proper divisors (20490181956708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331131113020 is a wasteful number, since it uses less digits than its factorization.
11331131113020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 560392590 (or 560392588 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 11331131113020 its reverse (2031113113311), we get a palindrome (13362244226331).
The spelling of 11331131113020 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred thirteen thousand, twenty".
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