11331131300 has 72 divisors (see below), whose sum is σ = 25166889216. Its totient is φ = 4426274560.

The previous prime is 11331131299. The next prime is 11331131323. The reversal of 11331131300 is 313113311.

11331131300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2361704 + ... + 2366496.

It is an arithmetic number, because the mean of its divisors is an integer number (349540128).

Almost surely, 2^11331131300 is an apocalyptic number.

11331131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11331131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12583444608).

11331131300 is an abundant number, since it is smaller than the sum of its proper divisors (13835757916).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11331131300 is a wasteful number, since it uses less digits than its factorization.

11331131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5357 (or 5350 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11331131300 its reverse (313113311), we get a palindrome (11644244611).

The spelling of 11331131300 in words is "eleven billion, three hundred thirty-one million, one hundred thirty-one thousand, three hundred".