Base | Representation |
---|---|
bin | 1010010011100111000111… |
… | …0100001001100101011000 |
3 | 1111010022221212202001001012 |
4 | 2210321301310021211120 |
5 | 2441131001001114000 |
6 | 40033510355513052 |
7 | 2246466230050460 |
oct | 244716164114530 |
9 | 44108855661035 |
10 | 11332033223000 |
11 | 3679985368826 |
12 | 1330282bb8788 |
13 | 6427b5925089 |
14 | 2b268ab88ba0 |
15 | 149b8b218735 |
hex | a4e71d09958 |
11332033223000 has 64 divisors (see below), whose sum is σ = 30305094580800. Its totient is φ = 3885268531200.
The previous prime is 11332033222999. The next prime is 11332033223011. The reversal of 11332033223000 is 32233023311.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 809423945 + ... + 809437944.
It is an arithmetic number, because the mean of its divisors is an integer number (473517102825).
Almost surely, 211332033223000 is an apocalyptic number.
11332033223000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11332033223000 is an abundant number, since it is smaller than the sum of its proper divisors (18973061357800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11332033223000 is a wasteful number, since it uses less digits than its factorization.
11332033223000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1618861917 (or 1618861903 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 11332033223000 its reverse (32233023311), we get a palindrome (11364266246311).
The spelling of 11332033223000 in words is "eleven trillion, three hundred thirty-two billion, thirty-three million, two hundred twenty-three thousand".
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