Base | Representation |
---|---|
bin | 110100110001001111… |
… | …1000000001100110111 |
3 | 101211111120021211012010 |
4 | 1221202133000030313 |
5 | 3324040242203101 |
6 | 124020435455303 |
7 | 11121132245046 |
oct | 1514237001467 |
9 | 354446254163 |
10 | 113321444151 |
11 | 44072001283 |
12 | 19b67157533 |
13 | a8bc679a86 |
14 | 56b038255d |
15 | 2e339d42d6 |
hex | 1a627c0337 |
113321444151 has 8 divisors (see below), whose sum is σ = 159983215344. Its totient is φ = 71103651200.
The previous prime is 113321444147. The next prime is 113321444237. The reversal of 113321444151 is 151444123311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113321444151 - 22 = 113321444147 is a prime.
It is a super-2 number, since 2×1133214441512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113321444111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1110994500 + ... + 1110994601.
It is an arithmetic number, because the mean of its divisors is an integer number (19997901918).
Almost surely, 2113321444151 is an apocalyptic number.
113321444151 is a deficient number, since it is larger than the sum of its proper divisors (46661771193).
113321444151 is a wasteful number, since it uses less digits than its factorization.
113321444151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2221989121.
The product of its digits is 5760, while the sum is 30.
Adding to 113321444151 its reverse (151444123311), we get a palindrome (264765567462).
The spelling of 113321444151 in words is "one hundred thirteen billion, three hundred twenty-one million, four hundred forty-four thousand, one hundred fifty-one".
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