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11341201301 is a prime number
BaseRepresentation
bin10101000111111110…
…01111111110010101
31002021101110201102122
422203333033332111
5141211321420201
65113213145325
7551021422553
oct124377177625
932241421378
1011341201301
11489a8a3441
12224618b245
1310b981ca01
1479832abd3
154659dae1b
hex2a3fcff95

11341201301 has 2 divisors, whose sum is σ = 11341201302. Its totient is φ = 11341201300.

The previous prime is 11341201283. The next prime is 11341201331. The reversal of 11341201301 is 10310214311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6416811025 + 4924390276 = 80105^2 + 70174^2 .

It is an emirp because it is prime and its reverse (10310214311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11341201301 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11341201301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11341201331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670600650 + 5670600651.

It is an arithmetic number, because the mean of its divisors is an integer number (5670600651).

Almost surely, 211341201301 is an apocalyptic number.

It is an amenable number.

11341201301 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341201301 is an equidigital number, since it uses as much as digits as its factorization.

11341201301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11341201301 its reverse (10310214311), we get a palindrome (21651415612).

The spelling of 11341201301 in words is "eleven billion, three hundred forty-one million, two hundred one thousand, three hundred one".