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11343002117 is a prime number
BaseRepresentation
bin10101001000001100…
…00111101000000101
31002021111212012200112
422210012013220011
5141212302031432
65113315522405
7551042633006
oct124406075005
932244765615
1011343002117
1148a0913417
1222468b9405
1310ba000595
147986791ad
15465c447b2
hex2a4187a05

11343002117 has 2 divisors, whose sum is σ = 11343002118. Its totient is φ = 11343002116.

The previous prime is 11343002101. The next prime is 11343002141. The reversal of 11343002117 is 71120034311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7299822721 + 4043179396 = 85439^2 + 63586^2 .

It is a cyclic number.

It is not a de Polignac number, because 11343002117 - 24 = 11343002101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11343002092 and 11343002101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11343002197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671501058 + 5671501059.

It is an arithmetic number, because the mean of its divisors is an integer number (5671501059).

Almost surely, 211343002117 is an apocalyptic number.

It is an amenable number.

11343002117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343002117 is an equidigital number, since it uses as much as digits as its factorization.

11343002117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 11343002117 its reverse (71120034311), we get a palindrome (82463036428).

The spelling of 11343002117 in words is "eleven billion, three hundred forty-three million, two thousand, one hundred seventeen".