Base | Representation |
---|---|
bin | 11001110010101010110101… |
… | …100111000011011110011110 |
3 | 112212122002202002100110010002 |
4 | 121302222311213003132132 |
5 | 104331442024044420220 |
6 | 1041130243443014302 |
7 | 32615162533322336 |
oct | 3162526547033636 |
9 | 485562662313102 |
10 | 113433133201310 |
11 | 331637a355086a |
12 | 1088012696a392 |
13 | 4b3a910985950 |
14 | 200229b6020c6 |
15 | d1a9c957ec75 |
hex | 672ab59c379e |
113433133201310 has 32 divisors (see below), whose sum is σ = 219888627799680. Its totient is φ = 41882457904128.
The previous prime is 113433133201307. The next prime is 113433133201321. The reversal of 113433133201310 is 13102331334311.
It is a happy number.
It is a super-2 number, since 2×1134331332013102 (a number of 29 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4416974 + ... + 15696366.
It is an arithmetic number, because the mean of its divisors is an integer number (6871519618740).
Almost surely, 2113433133201310 is an apocalyptic number.
113433133201310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113433133201310 is a deficient number, since it is larger than the sum of its proper divisors (106455494598370).
113433133201310 is a wasteful number, since it uses less digits than its factorization.
113433133201310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11356772.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 113433133201310 its reverse (13102331334311), we get a palindrome (126535464535621).
The spelling of 113433133201310 in words is "one hundred thirteen trillion, four hundred thirty-three billion, one hundred thirty-three million, two hundred one thousand, three hundred ten".
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