Base | Representation |
---|---|
bin | 110100110110100100… |
… | …0101000101011010000 |
3 | 101211222000112000002112 |
4 | 1221231020220223100 |
5 | 3324422013130000 |
6 | 124050301404452 |
7 | 11125432121045 |
oct | 1515510505320 |
9 | 354860460075 |
10 | 113500130000 |
11 | 44153956634 |
12 | 19bb6b69728 |
13 | a91a6b074a |
14 | 56c9db71cc |
15 | 2e4452d235 |
hex | 1a6d228ad0 |
113500130000 has 50 divisors (see below), whose sum is σ = 274795188954. Its totient is φ = 45400048000.
The previous prime is 113500129949. The next prime is 113500130017. The reversal of 113500130000 is 31005311.
It can be written as a sum of positive squares in 5 ways, for example, as 70284372544 + 43215757456 = 265112^2 + 207884^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 5665007 + ... + 5685006.
Almost surely, 2113500130000 is an apocalyptic number.
113500130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113500130000 is an abundant number, since it is smaller than the sum of its proper divisors (161295058954).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113500130000 is an equidigital number, since it uses as much as digits as its factorization.
113500130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11350041 (or 11350020 counting only the distinct ones).
The product of its (nonzero) digits is 45, while the sum is 14.
Adding to 113500130000 its reverse (31005311), we get a palindrome (113531135311).
The spelling of 113500130000 in words is "one hundred thirteen billion, five hundred million, one hundred thirty thousand".
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