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113513114335 = 579287374973
BaseRepresentation
bin110100110110111101…
…0001010101011011111
3101211222220221200020211
41221231322022223133
53324433324124320
6124051443553251
711125650360205
oct1515572125337
9354886850224
10113513114335
1144160214995
1219bbb38b827
13a9202a879a
1456cb9d7075
152e4574555a
hex1a6de8aadf

113513114335 has 8 divisors (see below), whose sum is σ = 137939987520. Its totient is φ = 89660991264.

The previous prime is 113513114287. The next prime is 113513114381. The reversal of 113513114335 is 533411315311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113513114335 - 217 = 113512983263 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113513114297 and 113513114306.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143687092 + ... + 143687881.

It is an arithmetic number, because the mean of its divisors is an integer number (17242498440).

Almost surely, 2113513114335 is an apocalyptic number.

113513114335 is a deficient number, since it is larger than the sum of its proper divisors (24426873185).

113513114335 is an equidigital number, since it uses as much as digits as its factorization.

113513114335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287375057.

The product of its digits is 8100, while the sum is 31.

Adding to 113513114335 its reverse (533411315311), we get a palindrome (646924429646).

The spelling of 113513114335 in words is "one hundred thirteen billion, five hundred thirteen million, one hundred fourteen thousand, three hundred thirty-five".

Divisors: 1 5 79 395 287374973 1436874865 22702622867 113513114335