| Base | Representation |
|---|---|
| bin | 10101001001010001… |
| … | …11111000111100001 |
| 3 | 1002022011001120200000 |
| 4 | 22210220333013201 |
| 5 | 141222122023210 |
| 6 | 5114243450213 |
| 7 | 551213421540 |
| oct | 124450770741 |
| 9 | 32264046600 |
| 10 | 11352142305 |
| 11 | 48a5a96599 |
| 12 | 2249986969 |
| 13 | 10bbb8098a |
| 14 | 799978157 |
| 15 | 46694cac0 |
| hex | 2a4a3f1e1 |
11352142305 has 96 divisors (see below), whose sum is σ = 23368310784. Its totient is φ = 5179018176.
The previous prime is 11352142303. The next prime is 11352142331. The reversal of 11352142305 is 50324125311.
11352142305 is a `hidden beast` number, since 1 + 1 + 352 + 1 + 4 + 2 + 305 = 666.
11352142305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11352142305 - 21 = 11352142303 is a prime.
It is a super-2 number, since 2×113521423052 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11352142303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 5501704 + ... + 5503766.
It is an arithmetic number, because the mean of its divisors is an integer number (243419904).
Almost surely, 211352142305 is an apocalyptic number.
11352142305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11352142305 is an abundant number, since it is smaller than the sum of its proper divisors (12016168479).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11352142305 is an equidigital number, since it uses as much as digits as its factorization.
11352142305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2737 (or 2725 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 11352142305 its reverse (50324125311), we get a palindrome (61676267616).
The spelling of 11352142305 in words is "eleven billion, three hundred fifty-two million, one hundred forty-two thousand, three hundred five".
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